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What is the minimum standard size overcurrent protective device required for a 120/208-volt, 3-phase feeder supplying a continuous load of 37.5 kVA?

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To determine the minimum standard size overcurrent protective device for a 120/208-volt, 3-phase feeder supplying a continuous load of 37.5 kVA, it is essential to first calculate the continuous load in amperes and then apply the appropriate standards for overcurrent protection.

The formula to convert kilovolt-amperes (kVA) to amperes (A) for a three-phase load is:

\[

I = \frac{P}{\sqrt{3} \times V}

\]

Where:

- \( I \) is the current in amperes

- \( P \) is the load in watts (or kVA converted to watts)

- \( V \) is the voltage (line-to-line for three-phase, which in this case is 208 volts)

The continuous load is 37.5 kVA, which can be expressed in watts as:

\[

37.5 \, \text{kVA} \times 1000 = 37500 \, \text{VA}

\]

Now we can substitute the values into the formula:

\[

I = \frac{37500 \, \text{VA}}{\sqrt{3} \times 208 \,

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